x(4+x)+20=x^2-(x-5)

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Solution for x(4+x)+20=x^2-(x-5) equation:


Simplifying
x(4 + x) + 20 = x2 + -1(x + -5)
(4 * x + x * x) + 20 = x2 + -1(x + -5)
(4x + x2) + 20 = x2 + -1(x + -5)

Reorder the terms:
20 + 4x + x2 = x2 + -1(x + -5)

Reorder the terms:
20 + 4x + x2 = x2 + -1(-5 + x)
20 + 4x + x2 = x2 + (-5 * -1 + x * -1)
20 + 4x + x2 = x2 + (5 + -1x)

Reorder the terms:
20 + 4x + x2 = 5 + -1x + x2

Add '-1x2' to each side of the equation.
20 + 4x + x2 + -1x2 = 5 + -1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
20 + 4x + 0 = 5 + -1x + x2 + -1x2
20 + 4x = 5 + -1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
20 + 4x = 5 + -1x + 0
20 + 4x = 5 + -1x

Solving
20 + 4x = 5 + -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
20 + 4x + x = 5 + -1x + x

Combine like terms: 4x + x = 5x
20 + 5x = 5 + -1x + x

Combine like terms: -1x + x = 0
20 + 5x = 5 + 0
20 + 5x = 5

Add '-20' to each side of the equation.
20 + -20 + 5x = 5 + -20

Combine like terms: 20 + -20 = 0
0 + 5x = 5 + -20
5x = 5 + -20

Combine like terms: 5 + -20 = -15
5x = -15

Divide each side by '5'.
x = -3

Simplifying
x = -3

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